(2^3x)(4^x-1)=(1/8)^2x

Simple and best practice solution for (2^3x)(4^x-1)=(1/8)^2x equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (2^3x)(4^x-1)=(1/8)^2x equation: 



(2^3x)(4^x-1)=(1/8)^2x

We move all terms to the left:

(2^3x)(4^x-1)-((1/8)^2x)=0



Domain of the equation: 8)^2x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

2^3x(4^x-1)-((+1/8)^2x)=0

We multiply all the terms by the denominator


(2^3x(4^x-1))*8)^2x)-((+1=0

We move all terms containing x to the left, all other terms to the right

(2^3x(4^x-1))*8)^2x)-((=-1

See similar equations:

| 18w-15w-3w-2w+11w-19=1 | | -1-10t=-8t-9 | | 16^x–2=2^2x | | x+6x+28=14 | | (x+2/2)=9-(x+6)/3 | | 18k+4k-21k-1=3 | | 5(y+6)+2y=-12 | | 3^2x-1=187 | | -1−10t=-8t−9 | | 5x+6(4x+15)=242 | | 9^2x^+1=1/27 | | 8h-15h=7 | | 19a-14a=15 | | -3(2-r)=18 | | 9x*x-x-216=0 | | -5j=j+6 | | !9x*x-x-216=0 | | 36^3x-4=6x^2 | | -5q=1-4q | | -14y+7y+14y-14=0 | | 5(34x−1)=2x. | | −2x−15=6x+9. | | -17v+14v-16v-6v-17=2 | | 7(x-2)=-2x+40 | | 39-2w=7-16w | | 18u-4u+u-10u+u=12 | | 6y+13=-63 | | –5(x–2)=50 | | 18u+4u-19u=15 | | 2=l-2 | | (2.1/3)y-5=16 | | 9n+3n-7n+1=6 |

Equations solver categories